I often need to determine the ordinal indicator (st/nd/rd/th) associated with a number, especially when I am working with dates. In this post, we will learn to write a simple user defined function in VBA, which will identify the ordinal indicator of an integer. Since the logic is quite straightforward, let us see how we can use the different control structures available in VBA.

### A quick refresher on English Ordinal Indicators

The general rule is: numbers ending with 1, 2 and 3, get the ordinal indicators ‘st’, ‘nd’ and ‘rd’ respectively. The exceptions to the previous rule are numbers ending with 11, 12 and 13, which get the ‘th’ indicator.

The rest of the numbers get the ‘th’ indicator.

### What are control Structures?

For those of you who are new to programming, in general, any code is executed one line after another. And control structures let you break that rule. They let us jump around unconditionally or conditionally. They even let us keep looping through lines. We will be focussing only on the control structures that let us jump around conditionally, which are generally referred to as Decision Structures.

The two popular decision structures available in VBA are:

Follow the links in the list for a detailed account on using these control structures. Although these links are related to VB.NET, and not VBA specifically, almost all the principles apply.

I highly recommend reading about the Select Case statement, as it allows you to implement complex decisions with minimal lines of code. I have used some of these principles in this post, and in the end, I will leave you with a weird way of using the Select Case statement, which I prefer over the If… Then… ElseIf… Else… structure.

Now let us take a look at how we can use the control structures to fetch the ordinal indicator of a number. Notice that I am using the Long data type to accept a number as it will let me work even with very large numbers. The integer data type would suffice for most use cases though.

### If… Then… Else

Here is the UDF written using the *If… Then… Else* structure:

Function OrdinalIndicator(ByVal Number As Long) As String If Number Mod 100 = 11 Or _ Number Mod 100 = 12 Or _ Number Mod 100 = 13 Then OrdinalIndicator = "th" ElseIf Number Mod 10 = 1 Then OrdinalIndicator = "st" ElseIf Number Mod 10 = 2 Then OrdinalIndicator = "st" ElseIf Number Mod 10 = 3 Then OrdinalIndicator = "rd" Else OrdinalIndicator = "th" End If OrdinalIndicator = Number & OrdinalIndicator End Function

### Select… Case

Here is the UDF written using the *Select… Case* Structure:

Function OrdinalIndicator(ByVal Number As Long) As String Select Case Number Mod 100 Case 11 To 13 OrdinalIndicator = "th" Case Else Select Case Number Mod 10 Case 1 OrdinalIndicator = "st" Case 2 OrdinalIndicator = "nd" Case 3 OrdinalIndicator = "rd" Case Else OrdinalIndicator = "th" End Select End Select OrdinalIndicator = Number & OrdinalIndicator End Function

Now that you have seen the regular implementation of the *Select.. Case* statement, let us look at the quirky way I promised earlier. You can pass *TRUE *as the test expression to the *Select *statement, and then use Boolean expression beside the *Case *statements to convert the *Select… Case* control structure into a compact *If… Then… ElseIf… Else* structure.

Let me show you what I mean:

Function OrdinalIndicator(ByVal Number As Long) As String Select Case True Case Number Mod 100 = 11, Number Mod 100 = 12, _ Number Mod 100 = 13 OrdinalIndicator = "th" Case Number Mod 10 = 1 OrdinalIndicator = "st" Case Number Mod 10 = 2 OrdinalIndicator = "nd" Case Number Mod 10 = 3 OrdinalIndicator = "rd" Case Else OrdinalIndicator = "th" End Select OrdinalIndicator = Number & OrdinalIndicator End Function

### Downloads

I hope that you learnt something new about control structures today. Click on the link below to download a workbook, which contains the three UDFs.

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